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1/2x^2+5=0
Domain of the equation: 2x^2!=0We multiply all the terms by the denominator
x^2!=0/2
x^2!=√0
x!=0
x∈R
5*2x^2+1=0
Wy multiply elements
10x^2+1=0
a = 10; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·10·1
Δ = -40
Delta is less than zero, so there is no solution for the equation
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